**infinity**. Why would you not give that as an option? Or do you truly not know?

Started by
Sandor
, Oct 21 2012 23:52

55 replies to this topic

Posted 22 October 2012 - 00:38

Any finite number divided by 0 equals infinity. Do what Joe USer says.

By dividing 1 by 0, you're asking the question: How many times does 0 fit into 1?

Each time you do what Joe USer says, you're ask that question.

An infinite amount of times. So in a sense, you can but at the same time you can't. It depends on what you want to do. You can't turn it around, like, multiply the quotient with 0 and you'll get 0. So, you have to break rules to use infinity. You can't say "impossible", you need to think outside the box. Infinity is a funny subject.

There's no definitive answer. It depends on the use of the division and the context.

Computers don't like dividing by zero because it runs a loop of*add* (adding a negative) to see how many times it fits and what's left results in the carry. Computers don't compute infinity. So to stop the processor from stalling, they've added an exception and you need to write code to catch that or check it before you divide.

Subtract (negative add) the dividend/numerator with the divisor/denominator until you reach zero. Do this until you can't subtract anymore and return the quotient. If the remainder is not 0 then set the carry-flag and write the remainder to X (depending on architecture).

http://www.youtube.com/watch?v=VjZyOTES6iQ

By dividing 1 by 0, you're asking the question: How many times does 0 fit into 1?

Each time you do what Joe USer says, you're ask that question.

An infinite amount of times. So in a sense, you can but at the same time you can't. It depends on what you want to do. You can't turn it around, like, multiply the quotient with 0 and you'll get 0. So, you have to break rules to use infinity. You can't say "impossible", you need to think outside the box. Infinity is a funny subject.

There's no definitive answer. It depends on the use of the division and the context.

Computers don't like dividing by zero because it runs a loop of

Subtract (negative add) the dividend/numerator with the divisor/denominator until you reach zero. Do this until you can't subtract anymore and return the quotient. If the remainder is not 0 then set the carry-flag and write the remainder to X (depending on architecture).

http://www.youtube.com/watch?v=VjZyOTES6iQ

Posted 22 October 2012 - 00:40

1/1 = 1

1/.5 = 2

1/.25 = 4

1/.125 = 8

1/.0625 = 16

1/.01 = 100

1/.001 = 1000

so, we see that when denominator goes decreasing result goes increasing keeping numerator constant. now lets presume that denominator is infinity away from zero and then we use it as denomintaor to divide 1 then we get closest to infinity. you can imagin it.

1/.5 = 2

1/.25 = 4

1/.125 = 8

1/.0625 = 16

1/.01 = 100

1/.001 = 1000

so, we see that when denominator goes decreasing result goes increasing keeping numerator constant. now lets presume that denominator is infinity away from zero and then we use it as denomintaor to divide 1 then we get closest to infinity. you can imagin it.

Posted 22 October 2012 - 00:55

1/1 = 1

1/.5 = 2

1/.25 = 4

1/.125 = 8

1/.0625 = 16

1/.01 = 100

1/.001 = 1000

so, we see that when denominator goes decreasing result goes increasing keeping numerator constant. now lets presume that denominator is infinity away from zero and then we use it as denomintaor to divide 1 then we get closest to infinity. you can imagin it.

Thank you, Sir BODMAS