| Can't receive some SMS messages (From Google, Evernote, etc) in Tablet, Media Devices & Smartphones |
|
|
| India's 2013 Mars mission in Science Discussion & News |
|
|
| Sony rejected EA Access for the PS4 because it's not worth the money in Gamers' Hangout |
|
|
| Which console should I get? in Gamers' Hangout |
|
|
| The Big Wrestling Thread! in The Sporting Arena |
|
Neowinian
Posted 22 November 2012 - 18:08
<?php
$arr = array('foo','bar','baz','blong');
echo json_encode($arr);
?>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script language="javascript">
$.ajax({
url: [i]url[/i],
dataType: 'json',
data: [i]data[/i],
success: [i]callback[/i]
});
echo $arr; //I KNOW THIS IS WRONG
</script>
http://seapip.com
Posted 22 November 2012 - 20:09
<?php
$arr = array('foo','bar','baz','blong');
session_start(); // start up your PHP session!
$_SESSION['arr'] = $arr
echo json_encode($arr);
?>html:<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script language="javascript">
$.ajax({
url: [i]url[/i],
dataType: 'json',
data: [i]data[/i],
success: [i]callback[/i]
});
//Yes this is php inside js LOLZ
$_SESSION['arr'] = $arr
echo $arr;
session_destroy(); //If you want to remove the global variable again
</script>
http://seapip.com
Posted 22 November 2012 - 20:34
you need to make the html into a php like this:thanks but i cant echo PHP in a html script
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script language="javascript">
$.ajax({
url: [i]url[/i],
dataType: 'json',
data: [i]data[/i],
success: [i]callback[/i]
});
<?php
$_SESSION['arr'] = $arr
echo $arr;
session_destroy(); //If you want to remove the global variable again
?>
</script>
so if you test this php file you shouldn't see the php but the php results when you check the page source from within the browser.
<input class="input" type="text" name="name" <?php if(preg_match('/(?i)msie [6-9]/',$_SERVER['HTTP_USER_AGENT'])) { echo 'value'; } else { echo 'placeholder'; }?>="Name" />
Posted 22 November 2012 - 20:37
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script language="javascript">
$.ajax({
url: "test.php",
dataType: 'json',
success: function(json) {
// json now holds the array ["foo", "bar", "baz", "blong"]
console.log(json);
}
});
</script>
OP
Neowinian
Posted 22 November 2012 - 20:41
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
<title>Google Maps - Moving point along a path</title>
<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?sensor=false"></script>
</head>
<body onunload="GUnload()">
<div id="map_canvas" style="width: 1000px; height: 800px;"></div>
<script type="text/javascript">
var map;
var mapOptions = { center:
<?php
$result = mysql_query("SELECT * FROM location ORDER BY id DESC LIMIT 1");
while($row = mysql_fetch_array($result)){
echo 'new google.maps.LatLng('.$row['latitude'].', '.$row['longitude'].'),';
}
?>
zoom: 14,
mapTypeId: google.maps.MapTypeId.ROADMAP };
function initialize() {
map = new google.maps.Map(document.getElementById("map_canvas"), mapOptions);
var userCoor = [
<?php
$result = mysql_query("SELECT * FROM location ORDER BY id DESC");
while($row = mysql_fetch_array($result)){
echo '["TIME:-'.$row['TRUEtime'].'<br>SPEED:-'.$row['speed'].'mph<br />DISTANCE:-'.$row['distance'].'km",'.$row['latitude'].', '.$row['longitude'].'],';
}
?>
];
var userCoorPath = [
<?php
$result = mysql_query("SELECT * FROM location ORDER BY id ");
while($row = mysql_fetch_array($result)){
echo 'new google.maps.LatLng('.$row['latitude'].', '.$row['longitude'].'),';
}
?>
]
var userCoordinate = new google.maps.Polyline({
path: userCoorPath,
strokeColor: "blue",
strokeOpacity: 1,
strokeWeight: 4
});
userCoordinate.setMap(map);
var infowindow = new google.maps.InfoWindow();
var marker, i;
var image = new google.maps.MarkerImage('green.png',
// This marker is 20 pixels wide by 32 pixels tall.
new google.maps.Size(20, 20),
// The origin for this image is 0,0.
new google.maps.Point(0,0),
// The anchor for this image is the base of the flagpole at 0,32.
new google.maps.Point(10, 10));
for (i = 0; i < userCoor.length; i++) {
marker = new google.maps.Marker({
position: new google.maps.LatLng(userCoor[i][1], userCoor[i][2]),
map: map,
icon : image
});
google.maps.event.addListener(marker, 'click', (function(marker, i) {
return function() {
infowindow.setContent(userCoor[i][0]);
infowindow.open(map, marker);
}
})(marker, i));
}
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
</body>
</html>
yes that is it now i have the array how do i get it globalAre you trying to access the array/json returned by test.php inside test.html?
If so, the PHP part is correct, but you need to access the json returned inside the callback:<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script> <script language="javascript"> $.ajax({ url: "test.php", dataType: 'json', success: function(json) { // json now holds the array ["foo", "bar", "baz", "blong"] console.log(json); } }); </script>
OP
Neowinian
Posted 22 November 2012 - 20:47
$.getJSON("test.php",
function(data){
userCoor = data;
document.write(data);
});
Dont work
$.getJSON("test.php",
function(data){
userCoor = data;
});
document.write(data);
Posted 22 November 2012 - 21:04
by global i mean this
works$.getJSON("test.php", function(data){ userCoor = data; document.write(data); });Dont work$.getJSON("test.php", function(data){ userCoor = data; }); document.write(data);
document.write(data);
$.getJSON("test.php",
function(data){
userCoor = data;
// Do something with the data, like pass it off to another function which modifies the DOM.
});
OP
Neowinian
Posted 22 November 2012 - 21:07
