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# Help Spies Crack

## 60 posts in this topic

Then why isn't the lower case "o" used elsewhere in the text. I think that the "Ao" is the cipher key i.e. A=o.

Good call. So if A=O how does one find the other letters?

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Well the number 27 at the end represents the number of individual groups of letters.

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Good call. So if A=O how does one find the other letters?

You would need an Alberti Cipher Disk, set the inner ring so that "o" is aligned under "A" on the outer ring and then message could be decoded. Like I said though, it could be a double encryption.

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Surely in this day and age, there is some software you can enter the code into and let it try millions of combinations of ways to find legible text ?

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I showed it to my three year old...

After a few seconds of looking it over; she looks up at me, says "You seriously can't figure this out? Sorry dad but I'm busy" and goes back to playing with her lalaloopsy doll.

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A = 10

B = 3

C = 3

D = 7

E = 9

F = 8

G = 0

H = 8

I = 4

J = 4

K =-7

L = 3

M = 2

N = 11

O = 7

P = 6

Q = 6

R = 10

S = 2

T = 5

U = 4

V =2

W = 2

X= 4

Y =3

Z =4

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Anyone wanna try using this wheel to see if they can make some sense of this. feel free. give it time to load

http://scratch.mit.edu/projects/niethammer/324752

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Anyone wanna try using this wheel to see if they can make some sense of this. feel free. give it time to load

http://scratch.mit.e...ethammer/324752

Nice find, I'll give it a try

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Good luck guys :)

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Nice find, I'll give it a try

Maybe the numbers at the end have something to do with the sliders?

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If its world war 2 era you would be better off starting with either enigma style encryption or a derivitive or if we can rely on it being a UK code iirc they used typex machines?

Either way you would probably need one of the code books from the time I suspect.

But still good luck, I will check on this thread from time to time as I find this stuff fascinating

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As the pigeon was found dead with the code still attached to its leg, then we can be pretty certain the message didn't get to the recipient

Messages sent via pigeon would probably be fairly important to the side who sent them / were supposed to receive them or they wouldn't have been sent.

Maybe it would be possible to filter out certain major WW-II events that were successful / known about, due to receiving the message prior to the event, and just look for events that went bad due to lack of communication / surprise attacks ?

Long shot in the dark but might help :)

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enigma machine allegedly?

`http://enigmaco.de/enigma/enigma.swf[/CODE]`

copy paste above into browser

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Just specs of ink, or a pattern to line up with the key card ?

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As the pigeon was found dead with the code still attached to its leg, then we can be pretty certain the message didn't get to the recipient

So since it was never received does that mean the recipients key may still exist?? Or maybe after X amount of time the recipient destroyed it anyway!?!

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So since it was never received does that mean the recipients key may still exist?? Or maybe after X amount of time the recipient destroyed it anyway!?!

Good thinking, probably destroyed but there is a more likely chance of it still existing if they never received it

Either that or every message after this one made no sense because they were always one decryption behind the message :p

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if a message was sent, then 2 people knew the decryption if two people know it at least so do many O.o just need to find the grandkids of all the spies in wwII

Who says it was only for one person?

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Who says it was only for one person?

There's a good chance that no 'one person' knew the entire decryption key on their own, much like holding the keys to a vault, two people have to unlock simultaneously with a key each

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If it is encoded using a one-time pad of the same length (highly likely) it's completely impossible to crack it.

Why?

Because cracking it would return every possible combination of words or sentences of that length. Uncrackable encryption exists but you need a key at least as long as your message.

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Without the code book it would be impossible to crack. If it were to be cracked how would it be proved to be the correct message?

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I decoded it, it says

All your pigeon are belong to us!

 Stupid double post due to neowin being incredible slow today[/edit]

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Here's the full paper. What does NURP 40 TW 194 and below mean. There were 2 copies sent, so there is hope!

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1525/6 more than likely references a book/phonebook/dictionary/bible page number/row number/word/letter number for the cipher key.

1525/6 more than likely references a book/phonebook/dictionary/bible page number/row number/word/letter number for the cipher key.

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I thought anything could be cracked, given enough time.

That logic makes no sense lol you have to have something / someone who knows the code to verify whether or not you're correct..

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That logic makes no sense lol you have to have something / someone who knows the code to verify whether or not you're correct..

Unless the key you come up with for a WW-II dead pigeon's leg letter reads: "Attack London - Signed Adolf" - I would say you could be pretty sure you cracked it then ;)

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