figgy Posted October 22, 2012 Share Posted October 22, 2012 9 eligible bachelors and 6 single women buy tickets in the same 15-seat row theater. In how many ways can pairs of adjacent seats are ticketted to form eligible couples? For example: A seating arrangement like M M F M M F M F F M F M F M M gives 10 possible pairs (i.e 5 MF pairs and 5 FM pairs). Link to comment Share on other sites More sharing options...
n_K Posted October 22, 2012 Share Posted October 22, 2012 If you've got a casio calculator, you'll be wanting to use the C button, for choose. e.g. 10c3 will give the the number of times 3 things can be picked from the 10 items. Link to comment Share on other sites More sharing options...
cooky560 Veteran Posted October 23, 2012 Veteran Share Posted October 23, 2012 on my casio calc 10c3 brings up 120 :rofl: Link to comment Share on other sites More sharing options...
GreenMartian Posted October 23, 2012 Share Posted October 23, 2012 9 eligible bachelors and 6 single women buy tickets in the same 15-seat row theater. In how many ways can pairs of adjacent seats are ticketted to form eligible couples? For example: A seating arrangement like M M F M M F M F F M F M F M M gives 10 possible pairs (i.e 5 MF pairs and 5 FM pairs). Even MMMMMMMMMFFFFFF would produce 1 possible pair. So could the question not be simplified to: how many different positions can you arrange 6 'identical items' (i.e. order doesn't matter) in a slot of 15? (or 9 items in 15 slots, which I assume would produce the same result)? Link to comment Share on other sites More sharing options...
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