session Posted November 25, 2003 Share Posted November 25, 2003 If the sequence log(n, 2) (log in base of 2 n), log(n, 4), log(n, x) is geometric, determine the value of x to the nearest tenth. The ans is 16.0 but how to do it :/ Thanks for the help :) Link to comment Share on other sites More sharing options...
session Posted November 25, 2003 Author Share Posted November 25, 2003 anyone? :s Link to comment Share on other sites More sharing options...
caustiK Posted November 25, 2003 Share Posted November 25, 2003 the geometric series comes from the base of the logarithm. here your r constant = 4 because 4(log (a(1),n))/2(log(a(0),n) = 2. a(3) = a(0)*r^3. a(3) = 2*2^3 = 2^4 = 16. Link to comment Share on other sites More sharing options...
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