Math Problem


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∑(n=0, 10): ∫[?(MM)?ⁿ - k] dM

Can anyone figure out this answer simplified for me? That would be super, thanks.

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∑(n=0, 10): ∫[?(MM)?ⁿ - k]dM

When do you get into this kind of stuff... calculus?

All I know is the part before the ":" hehe.

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When do you get into this kind of stuff... calculus?

All I know is the part before the ":" hehe.

yah, the part before the colon is all i know too hah, it looks so complex.

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Wait, I take that back... I know ? is plus or minus:pp and ∫ is derivative.

∫ = integral ;))

EDIT: and BTW, is this 'Calculus 3'?? I'm taking Calc 3 in the fall..... :happy::

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Wait, I take that back... I know ? is plus or minus:pp and ∫ is derivative.

Isn't f'(var) the derivative?

As far as I know ∫ is the integral symbol.

EDIT: rumbleph1sh beat me to it :pp>

bwx

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I think I remember something about k= constant in a class prior to precalc actually. I'm pretty sure k is a constant, yes, but I'd rather have NFC tell you.

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Wave,Jun 14 2004, 04:18] ∑(n=0, 10): ∫[?(MM)?ⁿ - k] dM

Can anyone figure out this answer simplified for me? That would be super, thanks.

I might know how do it if it's just postive or negative, not sure if you can just take two cases...

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I have absolutely NO idea if my working is right, and I would bet that it is wrong, seeing I don't really know how to handle the ? and I didn't do any sort of advanced calculus. Either way I like to have a go at these sorts of things to see how I do, so if you get the answer, show me how wrong I actually am:laugh::

I am assuming M and k are constants of some kind.

∑(n=0, 10): ∫[?(MM)?ⁿ - k] dM

∫[?(MM)?ⁿ - k] dM

= ∫[?(M)^4n - k] dM

= ∫ [? 4nlog(M) ? log(k)] dM

= ?(4nlog(M)?/2) ? log(k) + c (//Thanks to elliot, I forgot my constant as there are no limits of intergration).

= ?4nlog(M)? - 2log(k) + c

= ?M^8n - k^2 + c (//not sure about these last 2 lines, so you are probably better trying the answer 2 lines up)

Now from here you just sub n = 0 to 10 in and work out the addition of the series. I won't bother doing it seeing I don't know what M and K are equal to. :)pe this helps :)

Edited by Masereth
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Pff, looks way more complicated than i've seen before

I'd probably solve it like this with the calculas i have been taught (not much)

(MM)/(2n+1) -kM + c

I haven't done it for ages though :p i might be a little rusty

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I wish NFC would explain what this eqn is supposed to do... :whistle:

[offtopic]I don't know a lot about programming, I wish I knew much, much more, but I really like your sig haha.[/offtopic]

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