Hypercube Posted June 16, 2004 Share Posted June 16, 2004 Any strategies to integrate [csc(x/2)]^(1/2)? The square root is the largest issue. Suggestions? Thanks in advance. Link to comment Share on other sites More sharing options...
rumbleph1$h Posted June 16, 2004 Share Posted June 16, 2004 I believe you can use the rule: ∫csc ⁿ u du = - ([csc ⁿ-? u cot u] / [n+1]) + ([n-2]/[n-1])∫csc ⁿ-? u du and simplify it from there;);) Link to comment Share on other sites More sharing options...
Hypercube Posted June 16, 2004 Author Share Posted June 16, 2004 Thanks. Link to comment Share on other sites More sharing options...
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