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[JAVA] n00b


Question

Hi.

So we had to make this program at college that prints the sum, subtraction and multiplication of two numbers with floating point..

I compiled there with the 4.2 version... and got no issues.

Now, I recompiled at home, with the new 5.0 version and I got this errors:

Calculos.java:13: possible loss of precision

found?  : double

required: float

? ? ? ? ? ? ?  a = 3.7;

? ? ? ? ? ? ? ? ?  ^

Calculos.java:14: possible loss of precision

found?  : double

required: float

? ? ? ? ? ? ?  b = 6.67;

? ? ? ? ? ? ? ? ?  ^

2 errors

I don't understand what's going on.

Can someone please explain w:) those errors occured? Thanks. :)

The Code:

/**
 * Programa que imprime a soma, a diferen?a e o produto de dois n?meros
 * de v?rgula flutuante ? minha escolha
 * 
 * @author Tiago F. Silva
 * @version Introdu??o ? Programa??o 2004/2005
 */
public class Calculos {

 ? ? ? public static void main(String[] arg) {

 ? ? ? ?float a,b;
 ? ? ? ?a = 3.7;
 ? ? ? ?b = 6.67;

 ? ? ? System.out.println("A soma de " + a + "+" + b + " ? " + (a+b));
 ? ? ? System.out.println("A diferen?a de " + a + "-" + b + " ? " + (a-b));
 ? ? ? System.out.println("O produto de " + a + "*" + b + " ? " + (a*b));
 ? ? ? }

}

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try a = (float) 3.7

alternatively, you can do Float floatA = new Float(3.7) and than use floatA.floatValue .. it's something like that, i don't remeber the exact syntax

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try a = (float) 3.7

alternatively, you can do Float floatA = new Float(3.7) and than use floatA.floatValue .. it's something like that, i don't remeber the exact syntax

Hmmm i wouldn't actually create an object just to by pass that, it's not necessary. Usually a simple casting would be enough, basically java just wants you to confirm that you know a loss of precision will occur and a casting would take care of it.

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