Can YOU solve this....?


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Originally posted by yashiro

hmmm...

They all ate the same (8/3)loaf or 2.666r

A gave away (7/3)loaf or 2.333r

B gave away (1/3)loaf or 0.333r

C paid 8g for (8/3)loaf so 1g = (1/3)loaf

Hence:

A should get 7g and B gets 1g.

Thankyou. :)

Who said they all ate the same amount? In fact, the 1st 2 guys started eating before inviting the 3rd -- according to the 1st post.

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"MAN B said that they should share the gold (4 pieces each) because everyone ate the same amount."

MAN B said it Dufus. 7 to MAN A and 1 to MAN B is fair.

MAN A gave up (15/3) - (8/3) = 7/3

2 2/3 (8/3) is the amount he ate.

MAN B gave up (9/3) - (8/3) = 1/3

2 2/3 (8/3) is the amount he ate.

7/3 - Man A's contribution

1/3 - Man B's contribution.

Me thinks.

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I have a problem maybe someone can solve it:

Let A be a ring with identity. Show that A is an integral domain if and only if deg(p(x)*q(x)) = deg(p(x)) + deg(q(x)) for all p(x), q(x) element of A[x].

Thanx.

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Originally posted by arsekicker

"MAN B said that they should share the gold (4 pieces each) because everyone ate the same amount."

MAN B said it Dufus. 7 to MAN A and 1 to MAN B is fair.

MAN A gave up (15/3) - (8/3) = 7/3

2 2/3 (8/3) is the amount he ate.

MAN B gave up (9/3) - (8/3) = 1/3

2 2/3 (8/3) is the amount he ate.

7/3 - Man A's contribution

1/3 - Man B's contribution.

Me thinks.

Missed that, it's late. Dufus is a bit harsh, eh???:D

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Originally posted by Knoxca

I have a problem maybe someone can solve it:

Let A be a ring with identity. Show that A is an integral domain if and only if deg(p(x)*q(x)) = deg(p(x)) + deg(q(x)) for all p(x), q(x) element of A[x].

Thanx.

Say wat :s

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hehe this was not for homework.....Im doing ISLAMIC HIGHER EDUCATION studies and this too place many years ago.

Anyway anotherway of looking at it:

8 pieces of bread, each man ate the same amount. So then beak each loaf into 3 pieces (hence for 3 men). You now have 24 pieces. From MAN A's loaf he ate 8 pieces and 7 of his pieces went to MAN C. From MAN B's loaf, he ate 8 pieces and 1 piece went to MAN C. So MAN A contributed 7 pieces while MAN B only contributed 1 piece to MAN C.............FAIR

thats why u have 7 pieces of gold for MAN A and 1 for MAN B.

We like to think with our hearts before our brain. hehehe.,..let the heart pump the blood folks.....and start using our brains a little bit.

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well ok, i think that considering the fact that man A and man B bought the bread (obviously for 1 piece of gold each since C gave them 8 pieces of gold) Man A paid 5 for his, Man B paid 3 for his, Man C ate the bread as well but he paid for it so they should get what they originally paid in the first place.

Man A gets 5

Man B gets 3

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Originally posted by Kareemah

hehe this was not for homework.....Im doing ISLAMIC HIGHER EDUCATION studies and this too place many years ago.

Anyway anotherway of looking at it:

8 pieces of bread, each man ate the same amount. So then beak each loaf into 3 pieces (hence for 3 men). You now have 24 pieces. From MAN A's loaf he ate 8 pieces and 7 of his pieces went to MAN C. From MAN B's loaf, he ate 8 pieces and 1 piece went to MAN C. So MAN A contributed 7 pieces while MAN B only contributed 1 piece to MAN C.............FAIR

thats why u have 7 pieces of gold for MAN A and 1 for MAN B.

We like to think with our hearts before our brain. hehehe.,..let the heart pump the blood folks.....and start using our brains a little bit.

yeah, but why did A give loaf to B? and B to A?

doesn't make sence

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No gold pieces are rightfully Man B's

there are no damages available here.

There was no contract, and each person gave their bread free from any compensation.

The gold pieces were a donation, and thus should follow the intent of the donor.

As such each person should receive 4 pieces.

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