Math Help Plz


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well im one of the lazyiest ppl in the world and i have gotten an assignment that im not to sure how to do, well at least some of the questions and i was wondering if anyone of the neowin math wizes can help me out ?

heres what the worksheet looks like, hope you can help.

Picture.jpg

Thanx.

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because the math teacher wants us to write the let statements and figure out the qudratic functions like y=a(x+h)2+k. so that the answer matches the one on bottom.

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Originally posted by Pyro

because the math teacher wants us to write the let statements and figure out the qudratic functions like y=a(x+h)2+k. so that the answer matches the one on bottom.

oh i see...if i knew algebra i would help ya...

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So easy, looks like kiddie calculus to me. (max/min problems)

Being an UberCal student with a 97 in that class, let me give you some general hints (it's so easy, even AOLers could do it!)

find a connection between two equation,

that's the hardest step, taking F'(x) should be easy for most of them.

Take the F'(x) of the equation, make it F'(x)=0 and solve for x

you should have vale that goes like + 0 - for max problems and - 0 + for min problems.

if you don't know any cal. you are gonna do this the hard way by using algebra, but I never had it this way, can't help you with that

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i figured out the first one...

Let X = First #

Let 60 - X = Seccond #

(X)(60 - X)

-(X? + 60x)

C= 60

2

C= 30?

C= 900

-(X? + 60x + 900 - 900)

-(X? + 60x + 900) + 900

-(X + 30) + 900

This is a MAXIMUM and the 2 numbers are (30 , 30)

Hope that will get some ppl to try and help me figure out the rest.

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Originally posted by Pyro

i figured out the first one...

Let X = First #

Let 60 - X = Seccond #

(X)(60 - X)

-(X? + 60x)

C= 60

2

C= 30?

C= 900

-(X? + 60x + 900 - 900)

-(X? + 60x + 900) + 900

-(X + 30) + 900

This is a MAXIMUM and the 2 numbers are (30 , 30)

Hope that will get some ppl to try and help me figure out the rest.

I don't think you're supposed to use the quadratic formula for MAX/MIN questions, because you have no way of knowing if your answeres are really Maximums. A Maximum occurs when the second derivative < 0, and a min occurs when it is > 0.

Here's how I learned to do it:

Let the 1st # = X

Let the 2nd # = Y

Given: X + Y = 60 and XY = MAX

therefore: Y = 60 - X

so XY becomes

X(60 - X)

=60X ? X?

then take the derivitive

dy = 60 - 2X

dx

2X = 60

X = 30

2nd Derivative:

d?Y = - 2

dx?

which is negative for all X values (as there is no X) so you know you have a Max.

To find Y: Y = 60 - 30 = 30

The two numbers are 30 and 30.

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well...

-(X + 30) + 900

the reason why i know that thats a max is because...

-(X + 30) + 900

/

the minus tell me its a max if it was + it would be a min.

and if you wanted to knwo what the max or min was you look at this number -(X + 30)***+ 900 ***

so that makes this equation -(X + 30) + 900 a max of +900.

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Those are sooo easy.:right:In addition, I usually did my homework on my own at home, so that you would know how to do it and how to carry it out.

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I like math, the calculations I did where quite easy for me (ok, I am a university student, so it should be easy for me :smart:

Here are the solutions I found:

1: 30; 30

2: 14; 14

3: 50; 50

4: 17777.77 m

6:

a: t=1.5; h=11.025

b: t=3

c: h=7.056

I don't have the time to do the rest, I just wanted to check, if I am still capable solving some math ;)

Edit: OK. Sorry, I made a mistake on 4. And I didn't see the solutions... :D That's why one should allways read twice and check the results...

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huh ? heh are those the answers cause the answers are at the bottom the the sheet if you want em what i need to do it the work to show that i know how to do it.

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Originally posted by Pyro

forgot to add when we did some excamples she showed us using this way so im only thinking we should do it this way.

Thats probably smart. Doing it any other way than what you learned would more than likely make her suspicious that you're cheating. Especially if you're having difficulty with it to begin with.

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