Started by
Hardcore Til I Die
, Sep 04 2012 17:50

79 replies to this topic

Posted 05 September 2012 - 15:29

I was always told that things were done in this order.

So:

6 - 1 x 0 + 2 / 2

6 - (1 x 0) + (2 / 2)

6 - 0 + 1

7

It irks me how people are getting this wrong all over facebook. I recall being taught this at the age of 14 (ish - working out where I was in school based upon where I remember sitting).

People are typing it directly as shown into a calculator, and swearing blind that they are right - because the calculator says so. I have 2 A-Levels in Mathetmatics (pure and statistics) and yet people with less than a GSCE wish to tell me I am wrong. FML!

So:

6 - 1 x 0 + 2 / 2

6 - (1 x 0) + (2 / 2)

6 - 0 + 1

7

It irks me how people are getting this wrong all over facebook. I recall being taught this at the age of 14 (ish - working out where I was in school based upon where I remember sitting).

People are typing it directly as shown into a calculator, and swearing blind that they are right - because the calculator says so. I have 2 A-Levels in Mathetmatics (pure and statistics) and yet people with less than a GSCE wish to tell me I am wrong. FML!

Posted 05 September 2012 - 16:07

My faith in humanity is restored as most people here are getting it right

People that get 1 think that you solve it left to right.

People that get 3.5 think that you solve it left to right AND 5x0 = 5.

I don't really call people thick or anything like that, but if people post calling others thick they should be damn sure they're right in the first place

it doesn't matter if you solve it left to right or right to left. Adding integers is most certainly a commutative operation

Posted 05 September 2012 - 17:34

I get 7. I think order is multiplication, division, summation, subtraction. So 1x0 =0; 2/2 = 1; 6-0+1=7. But I could be completely wrong. In science and engineering, only an idiot would write out an equation like that. Scientist and Engineers strive to be specific as possible in their formulations and add parenthesis for clarity even when they aren't needed.

Posted 05 September 2012 - 17:45

I was always told that things were done in this order.

So:

6 - 1 x 0 + 2 / 2

6 - (1 x 0) + (2 / 2)

6 - 0 + 1

7

It irks me how people are getting this wrong all over facebook. I recall being taught this at the age of 14 (ish - working out where I was in school based upon where I remember sitting).

People are typing it directly as shown into a calculator, and swearing blind that they are right - because the calculator says so. I have 2 A-Levels in Mathetmatics (pure and statistics) and yet people with less than a GSCE wish to tell me I am wrong. FML!

I don't mind people getting it wrong (so long as they're not accountants ), just hate the cockiness of people saying "You need to go back to school" etc. when they're actually wrong.

Who cares if people get it right or wrong.

The matter of the fact is you'll never see such an equation in a book as it would be a terrible book.

Seeing equations wrote like this one anger me more than people who fail to answer it.

I don't care if people get it wrong, it's the attitude of people who insist they're right and everyone else is an idiot even though they did it completely wrong. Someone even said to me "Who the hell are you to say what the order of operations is"

it doesn't matter if you solve it left to right or right to left. Adding integers is most certainly a commutative operation

By that I meant in the order that the sums appear. You need to do it in the BODMAS/PEMDAS order otherwise it's wrong.

Posted 05 September 2012 - 17:53

It's 7. However, BODMAS and PEDMAS are both silly; Division is the inverse of multiplication (special rule for divide by 0, of course) and subtraction is the inverse of addition, so they have the same priority, so you're supposed to do stuff left to right in that case.

For example:

6 % 2 == 6 * (0.5) and

6 - 3 == 6 + -3

So, if you used PEDMAS on 6*2-3+5*2, you'd end up doing addition before subtraction, that is, (6*2)-(3+(5*2)) == -1, which is obviously not the same as 6*2-3+5*2 == (((6*2)-3)+(5*2)) == 19

For example:

6 % 2 == 6 * (0.5) and

6 - 3 == 6 + -3

So, if you used PEDMAS on 6*2-3+5*2, you'd end up doing addition before subtraction, that is, (6*2)-(3+(5*2)) == -1, which is obviously not the same as 6*2-3+5*2 == (((6*2)-3)+(5*2)) == 19