Posted 01 March 2013 - 05:36
Posted 01 March 2013 - 05:42
Posted 01 March 2013 - 05:55
Posted 01 March 2013 - 06:35
SELECT Link FROM Links WHERE UserID in (SELECT UserID FROM Login WHERE Username = "articuno1au")Would return:
Posted 01 March 2013 - 18:23
Posted 02 March 2013 - 03:51
YounGMessiah, on 01 March 2013 - 18:23, said:
Posted 02 March 2013 - 06:10
Posted 02 March 2013 - 18:09
technikal, on 02 March 2013 - 06:10, said:
Posted 02 March 2013 - 23:09
hjf288, on 02 March 2013 - 20:28, said: