4 replies to this topic

[showlow]

The payroll program is supposed to accept a structure of the id number, name, hours, and rate of each employee. Then, the program is supposed to calculte the gross pay or each employee and display it along with the id number and name. My program is running without any compiler errors but the displayed output is incorrect and it only display one set of numbers not the 6 for each employee.

#include <stdio.h>
#include <stdlib.h>
#define NUMEMP 6
struct NetPay
{
int id;
char name[10];
double rate, hours;
};
int main()
{
int i;
double payment[6];
struct NetPay employee[NUMEMP] = {{3462, "Jones", 4.62, 40.0},
		  {6793, "Robbins", 5.83, 38.5},
		  {6985, "Smith", 5.22, 45.5},
		  {7834, "Swain", 6.89, 40.0},
		  {8867, "Timmins", 6.43, 35.5},
		  {9002, "Williams", 4.75, 42.0}};
for (i =0; i < NUMEMP; i++)
{
  payment[i]= employee[i].rate*employee[i].hours;
}
  printf("The gross pay of %d %s is %lf\n", employee[i].id, employee[i].name, payment[i]);
 
system ("pause");
return 0;
}

[bogas04]

showlow, on 29 April 2012 - 19:04, said:

The payroll program is supposed to accept a structure of the id number, name, hours, and rate of each employee. Then, the program is supposed to calculte the gross pay or each employee and display it along with the id number and name. My program is running without any compiler errors but the displayed output is incorrect and it only display one set of numbers not the 6 for each employee.

#include <stdio.h>
#include <stdlib.h>
#define NUMEMP 6
struct NetPay
{
int id;
char name[10];
double rate, hours;
};
int main()
{
int i;
double payment[6];
struct NetPay employee[NUMEMP] = {{3462, "Jones", 4.62, 40.0},
		  {6793, "Robbins", 5.83, 38.5},
		  {6985, "Smith", 5.22, 45.5},
		  {7834, "Swain", 6.89, 40.0},
		  {8867, "Timmins", 6.43, 35.5},
		  {9002, "Williams", 4.75, 42.0}};
for (i =0; i < NUMEMP; i++)
{
  payment[i]= employee[i].rate*employee[i].hours;
}
  printf("The gross pay of %d %s is %lf\n", employee[i].id, employee[i].name, payment[i]);

system ("pause");
return 0;
}

You haz put the printf statement outside the loop , hence u see the result for last member

Fix :

for (i =0; i < NUMEMP; i++)
{
  payment[i]= employee[i].rate*employee[i].hours;
printf("The gross pay of %d %s is %lf\n", employee[i].id, employee[i].name, payment[i]);
}

[showlow]

Ok thannk you! Hw would I display the total pay for all employees at the end?

[+Asik]

showlow, on 29 April 2012 - 20:01, said:

Ok thannk you! Hw would I display the total pay for all employees at the end?

Use a double that you declare before the loop and initialize at 0. Each time through the loop, add the employee's pay to it. Use a printf after the loop to display its value. I'd provide code but that would be doing your homework for you.

[showlow]

No that was plenty. Appreciate the help