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I have forgotten everything to do with sub-netting...


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#1 SPEhosting

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Posted 09 October 2012 - 17:01

Hi basically I learnt sub-netting 8 months ago... didnt touch it after I now have to do subnetting theory.... yay... and I have forgotten everything.....

maybe help me out with a few examples ? one of the many things I have to do is this...




156.192.162.56/255.255.255.0
Address Class : __b__

Bits Borrowed for Subnet: ____8_____
Bits for Host: ____8_____
Number of Usable Subnets: _____253_____
Number of Usable Hosts/Subnet: _________
Network Address: ____________________
Usable Address Range: __________
Broadcast Address: ____________________


I have put in some numbers though I think I am extremely wrong..... can you help me with this one and explain then maybe I can do the rest my self?


#2 Teebor

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Posted 09 October 2012 - 17:05

I would recommend going to networking-forum.com and looking on there as they have a good way to test yourself (one of the little links on the sidbar iirc) and also teaches you a good way to do it.

Another way to learn to do it is :-
http://www.subnettin..._to_subnet.html

Or are you looking for more detail?

#3 OP SPEhosting

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Posted 09 October 2012 - 17:52

View PostTeebor, on 09 October 2012 - 17:05, said:

I would recommend going to networking-forum.com and looking on there as they have a good way to test yourself (one of the little links on the sidbar iirc) and also teaches you a good way to do it.

Another way to learn to do it is :-
http://www.subnettin..._to_subnet.html

Or are you looking for more detail?

yea I understand that but its not helping with everything on my work haha xD I am so bummed

#4 +BudMan

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Posted 09 October 2012 - 20:34

so you want us to do your homework ;)

#5 trek

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Posted 09 October 2012 - 21:24

View PostSPEhosting, on 09 October 2012 - 17:01, said:

Hi basically I learnt sub-netting 8 months ago... didnt touch it after I now have to do subnetting theory.... yay... and I have forgotten everything.....

maybe help me out with a few examples ? one of the many things I have to do is this...

156.192.162.56/255.255.255.0
Address Class : __b__

Bits Borrowed for Subnet: ____8_____
Bits for Host: ____8_____
Number of Usable Subnets: _____253_____
Number of Usable Hosts/Subnet: _________
Network Address: ____________________
Usable Address Range: __________
Broadcast Address: ____________________


I have put in some numbers though I think I am extremely wrong..... can you help me with this one and explain then maybe I can do the rest my self?

156.192.162.56/255.255.255.0
Address Class : B

Bits Borrowed for Subnet: Class B is a 16-bit mask, but the SN above is a /24 so you borrowed 8 bits
Bits for Host: ____8_____
Number of Usable Subnets: 2^8 = 256 subnets
Number of Usable Hosts/Subnet: 32 bit address - 24 bit subnet address for a /24 = 8 bits for hosts -> 2^8 - 2 = 254 hosts per subnet
Network Address: 156.192.162.0/24
Usable Address Range: 156.192.162.0 to 156.192.162.254
Broadcast Address: 156.192.162.255

I'm pretty sure that's right... it's been a while since I passed my CCNA lol.

#6 Kami-

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Posted 09 October 2012 - 21:57

View PostBudMan, on 09 October 2012 - 20:34, said:

so you want us to do your homework ;)
This++

#7 OP SPEhosting

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Posted 09 October 2012 - 23:47

View Posttrek, on 09 October 2012 - 21:24, said:

156.192.162.56/255.255.255.0
Address Class : B

Bits Borrowed for Subnet: Class B is a 16-bit mask, but the SN above is a /24 so you borrowed 8 bits
Bits for Host: ____8_____
Number of Usable Subnets: 2^8 = 256 subnets
Number of Usable Hosts/Subnet: 32 bit address - 24 bit subnet address for a /24 = 8 bits for hosts -> 2^8 - 2 = 254 hosts per subnet
Network Address: 156.192.162.0/24
Usable Address Range: 156.192.162.0 to 156.192.162.254
Broadcast Address: 156.192.162.255

I'm pretty sure that's right... it's been a while since I passed my CCNA lol.

2^8 - 2 (the broadcast and the network address are not usable they are reserved ) but thanks for your help you confirmed most of my stuff

also its 1 to 255 0 and 256 are the resevered (the first and last addresses )

#8 +giantsnyy

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Posted 09 October 2012 - 23:52

View PostSPEhosting, on 09 October 2012 - 23:47, said:

2^8 - 2 (the broadcast and the network address are not usable they are reserved ) but thanks for your help you confirmed most of my stuff

also its 1 to 255 0 and 256 are the resevered (the first and last addresses )

Actually it would be 1 to 254.

0 is reserved for the network, 255 is reserved for the broadcast. 256 doesn't exist.

#9 OP SPEhosting

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Posted 10 October 2012 - 00:38

View Postgiantsnyy, on 09 October 2012 - 23:52, said:

Actually it would be 1 to 254.

0 is reserved for the network, 255 is reserved for the broadcast. 256 doesn't exist.
ha! why did i type 256 xD I just went into binary me thinks

#10 pes2013

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Posted 12 October 2012 - 23:11

View Postgiantsnyy, on 09 October 2012 - 23:52, said:

Actually it would be 1 to 254.

0 is reserved for the network, 255 is reserved for the broadcast. 256 doesn't exist.
Incorrect. 256 is Chuck Norris.

#11 moloko

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Posted 13 October 2012 - 09:15

Check out youtube. there are some great tutorials that have sped up my subnetting down to a minute or so.