I have forgotten everything to do with sub-netting...


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Hi basically I learnt sub-netting 8 months ago... didnt touch it after I now have to do subnetting theory.... yay... and I have forgotten everything.....

maybe help me out with a few examples ? one of the many things I have to do is this...

156.192.162.56/255.255.255.0

Address Class : __b__

Bits Borrowed for Subnet: ____8_____

Bits for Host: ____8_____

Number of Usable Subnets: _____253_____

Number of Usable Hosts/Subnet: _________

Network Address: ____________________

Usable Address Range: __________

Broadcast Address: ____________________

I have put in some numbers though I think I am extremely wrong..... can you help me with this one and explain then maybe I can do the rest my self?

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I would recommend going to networking-forum.com and looking on there as they have a good way to test yourself (one of the little links on the sidbar iirc) and also teaches you a good way to do it.

Another way to learn to do it is :-

http://www.subnettin..._to_subnet.html

Or are you looking for more detail?

yea I understand that but its not helping with everything on my work haha xD I am so bummed

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Hi basically I learnt sub-netting 8 months ago... didnt touch it after I now have to do subnetting theory.... yay... and I have forgotten everything.....

maybe help me out with a few examples ? one of the many things I have to do is this...

156.192.162.56/255.255.255.0

Address Class : __b__

Bits Borrowed for Subnet: ____8_____

Bits for Host: ____8_____

Number of Usable Subnets: _____253_____

Number of Usable Hosts/Subnet: _________

Network Address: ____________________

Usable Address Range: __________

Broadcast Address: ____________________

I have put in some numbers though I think I am extremely wrong..... can you help me with this one and explain then maybe I can do the rest my self?

156.192.162.56/255.255.255.0

Address Class : B

Bits Borrowed for Subnet: Class B is a 16-bit mask, but the SN above is a /24 so you borrowed 8 bits

Bits for Host: ____8_____

Number of Usable Subnets: 2^8 = 256 subnets

Number of Usable Hosts/Subnet: 32 bit address - 24 bit subnet address for a /24 = 8 bits for hosts -> 2^8 - 2 = 254 hosts per subnet

Network Address: 156.192.162.0/24

Usable Address Range: 156.192.162.0 to 156.192.162.254

Broadcast Address: 156.192.162.255

I'm pretty sure that's right... it's been a while since I passed my CCNA lol.

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156.192.162.56/255.255.255.0

Address Class : B

Bits Borrowed for Subnet: Class B is a 16-bit mask, but the SN above is a /24 so you borrowed 8 bits

Bits for Host: ____8_____

Number of Usable Subnets: 2^8 = 256 subnets

Number of Usable Hosts/Subnet: 32 bit address - 24 bit subnet address for a /24 = 8 bits for hosts -> 2^8 - 2 = 254 hosts per subnet

Network Address: 156.192.162.0/24

Usable Address Range: 156.192.162.0 to 156.192.162.254

Broadcast Address: 156.192.162.255

I'm pretty sure that's right... it's been a while since I passed my CCNA lol.

2^8 - 2 (the broadcast and the network address are not usable they are reserved ) but thanks for your help you confirmed most of my stuff

also its 1 to 255 0 and 256 are the resevered (the first and last addresses )

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2^8 - 2 (the broadcast and the network address are not usable they are reserved ) but thanks for your help you confirmed most of my stuff

also its 1 to 255 0 and 256 are the resevered (the first and last addresses )

Actually it would be 1 to 254.

0 is reserved for the network, 255 is reserved for the broadcast. 256 doesn't exist.

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Actually it would be 1 to 254.

0 is reserved for the network, 255 is reserved for the broadcast. 256 doesn't exist.

ha! why did i type 256 xD I just went into binary me thinks
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