• 0

Mathematical Table Using Squared, Cubed, Square-root, and Cubed Root


Question

I have to create a table exactly like the one in the attachment using squared, cubed, square-root, and cube root. I am having a hard time creating the code and been struggling for hours, can anyone point me towards the right direction or have the code do this? thanks

 

post-507579-0-23039300-1383783580.png

14 answers to this question

Recommended Posts

  • 0

I am pretty new at this but this is all I got so far:

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double x = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;

    cout << "Where would you like to start? ";
    cin >> x;
    cout << endl;

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;

    cout << " x sqrt(x) x^2\n\n x^3\n";

    squared = x*x;
    cubed = x*x*x;
    squareRoot = sqrt (x);
    cubeRoot = pow(x), 1/3;


    return 0;
}

  • 0

here is my updated one, I can't get it to stop looping. I want it to stop at the number of rows when the user enters it

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double number = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;

    cout << "Where would you like to start? ";
    cin >> number;
    cout << endl;

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;
        

    squared = number*number;
    cubed = number*number*number;
    squareRoot = sqrt (number);
    cubeRoot = pow((double)(number),(double)1/3);

    do
    {
    cout << number << "  " << squared << "  " << cubed << "  " << squareRoot << "  " << cubeRoot << "  " << ceiling << "  " << floor << "  " << endl;
    number++, squared++, cubed++, squareRoot++, cubeRoot++, ceiling++, floor++;
    }
    while (number > 0);


    return 0;
}

  • 0

Well obviously it isn't going to stop since you increment 'number' inside the loop and have 'while (number < 0)' as your condition. The instructions say use a for-loop, so use a for-loop.

 

http://code.wikia.com/wiki/For_loop

  • 0

okay I stopped it from looping but is there any suggestions you would suggest for me to revise my code to make it look like the table in the attachment?

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double number = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;

    cout << "Where would you like to start? ";
    cin >> number;
    cout << endl;

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;
        

    squared = number*number;
    cubed = number*number*number;
    squareRoot = sqrt (number);
    cubeRoot = pow((double)(number),(double)1/3);

    do
    {
    cout << number << "  " << squared << "  " << cubed << "  " << squareRoot << "  " << cubeRoot << "  " << ceiling << "  " << floor << "  " << endl;
    ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;
    break;
    }
    while (number > 0);


    return 0;
}

  • 0

do
     {
     cout << number << "  " << squared << "  " << cubed << "  " << squareRoot << "  " << cubeRoot << "  " << ceiling << "  " << floor << "  " << endl;
     ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;
     [b]break;[/b]
     }
     while (number > 0);
You don't want that (the break) there. It will exit the do...while loop immediately after the first line of output.

Also, the way you've written it you should be decrementing "number" rather than incrementing it, or you could create a second count variable and increment it until it reaches the target number. As it stands it will fail because "number" your starting calculation number so you *should* be using "rows" in the do loop test instead of "number". :)

EDIT: Ugh, sorry, misread. You want to test against rows, but obviously will want to continue incrementing number.

  • 0

okay I just revised this and removed the break, so do you got any suggestions how to revise my code from looping and make my table to look exactly like the one in the attachment?

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double number = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;

    while (number <= 0)
    {

    cout << "Where would you like to start? ";
    cin >> number;
    cout << endl;
    }

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;


    squared = number*number;
    cubed = number*number*number;
    squareRoot = sqrt (number);
    cubeRoot = pow((double)(number),(double)1/3);

    do
    {
    cout << number << setw(5) << squared << setw(5) << cubed << setw(5) << squareRoot << setw(5) << cubeRoot << setw(5) << ceiling << setw(5) << floor << setw(5);
    ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;
    }
    while (number > 0);


    return 0;
}

  • 0

You could use tabs instead of spaces. I think it's "\t" in C?

You still need to fix your while statement, too. Unless you enter a negative starting number it will always be greater than zero. Plus, you're outputting your rows in the loop so you need to be testing against that variable.

for (int rowCount = 0; rowCount < rows; rowCount++)

{

...code...

}

  • 0

is that the correct place where I place the " (int rowCount = 0; rowCount < rows; rowCount++) " ? I placed it before the "do", but it still loops

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double number = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;


    {

    cout << "Where would you like to start? ";
    cin >> number;
    cout << endl;
    }

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;


    squared = number*number;
    cubed = number*number*number;
    squareRoot = sqrt (number);
    cubeRoot = pow((double)(number),(double)1/3);

    for (int rowCount = 0; rowCount < rows; rowCount++)

    do
    {
    cout << number << setw(5) << squared << setw(5) << cubed << setw(5) << squareRoot << setw(5) << cubeRoot << setw(5) << ceiling << setw(5) << floor << setw(5);
    ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;

    }
    while (number > 0);


    return 0;
}

  • 0

No, it should replace the do...while construct. The assignment you posted said to use a for... loop.

     for (int rowCount = 0; rowCount < rows; rowCount++)
     {
     cout << number << setw(5) << squared << setw(5) << cubed << setw(5) << squareRoot << setw(5) << cubeRoot << setw(5) << ceiling << setw(5) << floor << setw(5);
     ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;

     }
  

     return 0;
 }
  • 0

thank you for helping to make the program to stop the loop but my values still display diagonally and not evenly line up like a regular table should. it looks really random and values are located everywhere:

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double number = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;


    {

    cout << "Where would you like to start? ";
    cin >> number;
    cout << endl;
    }

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;


    squared = number*number;
    cubed = pow(number, 3.0);
    squareRoot = sqrt (number);
    cubeRoot = pow(number, 1/3);

    for (int rowCount = 0; rowCount < rows; rowCount++)
     {
     cout << number << setw(5) << squared << setw(5) << cubed << setw(5) << squareRoot << setw(5) << cubeRoot << setw(5) << ceiling << setw(5) << floor << setw(5);
     ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;

     }
 

     return 0;
 }
 

  • 0

I tried adding the the titles for my table but they still look very uneven looking:

 

#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main()
{

    double number = 0;
    double rows = 0;
    double squared = 0;
    double cubed = 0;
    double squareRoot = 0;
    double cubeRoot = 0;
    int ceiling = 0;
    int floor = 0;


    {

    cout << "Where would you like to start? ";
    cin >> number;
    cout << endl;
    }

    cout << "And how many rows? ";
    cin >> rows;
    cout << endl;


    squared = number*number;
    cubed = pow(number, 3.0);
    squareRoot = sqrt (number);
    cubeRoot = pow(number, 1/3);

    cout << "Number" << setw(6) << "Squared" << setw(6) << "Cubed" << setw(6) << "SquareRoot" << setw(6) << "CubeRoot" << setw(6) << "Ceiling" << setw(6) << "Floor" << setw(6);

    for (int rowCount = 0; rowCount < rows; rowCount++)
    {
     cout << number << setw(6) << squared << setw(6) << cubed << setw(6) << squareRoot << setw(6) << cubeRoot << setw(6) << ceiling << setw(6) << floor << setw(6);
     ++number, ++squared, ++cubed, ++squareRoot, ++cubeRoot, ++ceiling, ++floor;

     }
 

     return 0;
 }
 

  • 0

How about you worry about logic first.

 

You need a for loop, right?

You don't even need to be storing them into variables.

This whole thing could be real simple.

 

Your only inputs come from the user, and there are only 2.

So.... the pseudocode logic then becomes:

 

// Get starting point n (double)

// Get number of rows (integer)

// Print header

// For each row, print the set of values for the row of data, incrementing n by 0.1 in the process

 

Your for-loop would then look like:

    for (int intRow = 0; intRow < intRows; intRow++)
    {

         // Output formatted n

         cout << n

 

         // Output formatted squared

         cout << n*n

 

         // Output formatted cubed

         cout << n*n*n

 

         // etc...

 

         // increment n by 0.1

         n += 0.1

     }

 

The point of the exercise is to understand the LOGIC, not to worry a ton about the formatting.

Does the LOGIC make more sense to you?

This topic is now closed to further replies.
  • Recently Browsing   0 members

    • No registered users viewing this page.
  • Posts

    • Windows 11 KB5094126 June 2026 Patch Tuesday update now available to download by Sayan Sen Microsoft has released the June 2026 Patch Tuesday updates for Windows 11 25H2, 24H2. The 25H2 and 24H2 update is provided via KB5094126 (manual download link below), build 26100.8655 on 24H2, and build 26200.8655 on 25H2, after applying the updates. Windows 11 23H2 is available under KB5082052 (build 22631.6936). Microsoft has not published changelog yet. We will update the article once it's out. [Update: It's out] [Secure Boot] With this update, Windows quality updates include additional high confidence device targeting data, increasing coverage of devices eligible to automatically receive new Secure Boot certificates. Devices receive the new certificates only after demonstrating sufficient successful update signals, maintaining a controlled and phased rollout. [Virtualization] Fixed: This update addresses an issue that could result in Stop errors HYPERVISOR_ERROR (0x20001) and KMODE_EXCEPTION_NOT_HANDLED (0x1E) after installing KB5089573 on some devices during system restarts, virtual machine operations, or while running some gaming applications Microsoft says there are no known issues. These updates will be available from Windows Update and should install automatically in most cases. If you would like to download these updates for offline installation, you can get them from the Microsoft Catalog website. You can find the update for 25H2/24H2 at this link.
    • Price Drop: Save 90% on ChatPlayground AI lifetime plan, and compare multiple AI models by Steven Parker Today's highlighted deal comes via our Apps + Software section of the Neowin Deals store, where for only a limited time, you can save up to 90% on ChatPlayground AI: Lifetime Subscriptions. ChatPlayground AI puts the world’s top AI models in one powerful interface, letting you enter a single prompt and instantly compare outputs from multiple models to choose the perfect response for your needs. Boost productivity and creativity with access to the latest AI giants like GPT-4o, Claude Sonnet 4, Gemini 1.5 Flash, DeepSeek V3, and dozens more — all in one window. Whether you’re chatting, coding, generating images, or refining prompts, ChatPlayground AI equips you with advanced tools like prompt engineering, image/PDF chat, saved conversations, and AI image creation, plus priority support to keep your workflow seamless. Access the world’s best AI models Side-by-Side Comparisons: Enter one prompt & instantly view results from multiple AI models to find the best output for your needs 40+ AI Models: Includes GPT-4o, Claude Sonnet 4, Gemini 1.5 Flash, DeepSeek V3, Llama, Perplexity, and many more Multi-Function Platform: Access AI for chat, image generation & coding all within a single interface Web Browser Extension: Offers a Chrome extension to seamlessly integrate the platform into your browsing workflow Boost productivity with powerful features ChatPlayground Interface: Designed for seamless AI model comparison in one window Prompt Engineering: Refine & optimize your prompts for better, more accurate responses Chat with Images & PDFs: Upload visuals and documents to get context-aware answers Saved Chat History: Keep track of past conversations for reference & ongoing projects AI Image Generation: Create high-quality visuals powered by top AI image models Priority Customer Support: Get faster assistance whenever you need it What you'll get with the Unlimited Plan Includes unlimited messages/month Built for prompt engineers, startups, and teams who run experiments nonstop Includes priority access to new features and future models Good to know Length of access: lifetime Redemption deadline: redeem your code within 30 days of purchase Access options: Desktop Max number of device(s): Unlimited Available to both NEW & Existing users Updates included A lifetime subscription to ChatPlayground AI (Unlimited Plan) normally costs $619, but you can pick it up for just $59.97 for a limited time - that represents a saving of $614 (90% off). Click the link below for more details, always check terms and specifications before making a purchase. Get this ChatPlayground AI (Unlimited) for $59.97 (was $619) There are also two other discounted plans to choose from. Although priced in U.S. dollars, this deal is available for digital purchase worldwide. Support queries If you have queries or need support for any of the Neowin Deals, please use the contact form here. Neowin Deals are managed and sold by StackCommerce who represent Neowin on an affiliate basis. Why we post these deals We post these because we earn commission on each sale so as not to rely solely on advertising, which many of our readers block. It all helps toward paying staff reporters, servers and hosting costs. So for those that keep moaning and complaining, be thankful we're still online for you to even do that. Other ways to support Neowin Whitelist Neowin by not blocking our ads Create a free member account to see fewer ads Make a donation to support our day to day running costs Subscribe to Neowin - for $14 a year, or $28 a year for an ad-free experience Disclosure: Neowin benefits from revenue of each sale made through our branded deals site powered by StackCommerce.
    • Amazon Deal: These AMD RX 9070 XT GPUs are very good offers by Sayan Sen Following the release of AMD's new RX 9070 GRE last week for $549 (our review), AMD currently has a couple of great deals on the more powerful 9070 XT wherein the GPU is on sale for $650. We already covered the Gigabyte Gaming model a couple of days ago which is still live at that price. Aside from that, the white ICE variant is also at the same price (purchase link under the specs table down below). This is interesting to note considering white cards are generally more expensive as they come with a premium attached. Similar to the Gaming model, the ICE card too employs Gigabyte's WINDFORCE cooling system which combines multiple design elements such as alternate-spinning Hawk fans, a vapor chamber, and composite heat pipes to manage heat dissipation. The Server-grade Thermal conductive gel further helps in this department. The inclusion of a semi-passive cooling mode allows the fans to remain inactive under low workloads, which allows for reduced noise operation during lighter usage. There is dual BIOS switch that allows toggling between performance and silent modes. The tech specs of the card are given in the table below: Specification Value Boost Clock Up to 3060 MHz (Reference Card: 2970 MHz) Game Clock Up to 2520 MHz (Reference Card: 2400 MHz) Stream Processors 4096 Memory Size 16 GB Memory Type GDDR6 Memory Clock 20 Gbps Memory Bus Width 256-bit PCI Express Interface PCI Express 5.0 Max Resolution 7680 × 4320 Maximum Displays Supported 4 Display Outputs 2 × DisplayPort 2.1a 2 × HDMI 2.1b Card Dimensions 288 × 132 × 56 mm (L × W × H) (2.7 slot) Recommended Power Supply 750 W Power Connectors 3 × 8-pin PCIe Get it at the link below: GIGABYTE Radeon™ RX 9070 XT Gaming OC ICE 16G Graphics Card (GV-R907XGAMINGOCICE-16GD): $649.99 (Sold and Shipped by Amazon US) (Was: $750) If your budget is lower, check this Nvidia RTX 5060 Ti 8GB deal out for only $330 wherein you get the latest James Bond game free. This Amazon deal is US-specific and not available in other regions unless specified. This is a first-party seller link (at the time of article publishing); ensure that you also purchase from a first-party seller link only. If you don't like it or want to look at more options, check out the previous deals that we have covered, OR you can also visit Amazon US deals page. Get Prime (SNAP), Prime Video, Audible Plus or Kindle / Music Unlimited. Free for 30 days. As an Amazon Associate, we earn from qualifying purchases.
    • What about it? The old MV2 version will not work.
  • Recent Achievements

    • Week One Done
      rubentuben8 earned a badge
      Week One Done
    • Week One Done
      ARaclen earned a badge
      Week One Done
    • One Year In
      jojodbn earned a badge
      One Year In
    • One Month Later
      jojodbn earned a badge
      One Month Later
    • Week One Done
      jojodbn earned a badge
      Week One Done
  • Popular Contributors

    1. 1
      +primortal
      516
    2. 2
      PsYcHoKiLLa
      229
    3. 3
      +Edouard
      118
    4. 4
      ATLien_0
      87
    5. 5
      Steven P.
      83
  • Tell a friend

    Love Neowin? Tell a friend!