[C] Displaying system date in yyyymmdd format?

[AaronMT]

Hello, I am producing a payroll and instead of asking the user for the date, I would like to display the system date in

yyyymmdd format

I am not sure how this would be done, I believe I need time.h header? But how to get it in that format I am unsure.

[kjordan2001]

Not sure if this is the best way, but it works:

char* s = malloc(sizeof(char)*8);

time_t t = time(0);

struct tm *lt = localtime(&t);

strftime(s,10,"%Y%m%d",lt);

printf("%s\n",s);

[AaronMT]

So far I researched this, which works

#include <time.h>

#include <stdio.h>

#include <sys/types.h>

#include <sys/timeb.h>

#include <string.h>

int main()

{

char tmpbuf[128];

_strdate( tmpbuf );

printf( "OS date:\t\t\t\t%s\n", tmpbuf );

}

no idea about getting it into 20041109 format

[AaronMT]

Oh awsome! That worked beautifully, thanks.

[kjordan2001]

  INFERNO2k said:

So far I researched this, which works

#include <time.h>

#include <stdio.h>

#include <sys/types.h>

#include <sys/timeb.h>

#include <string.h>

int main()

{

    char tmpbuf[128];

    _strdate( tmpbuf );

    printf( "OS date:\t\t\t\t%s\n", tmpbuf ); 

}

no idea about getting it into 20041109 format

584894758[/snapback]

Must be a Windows only thing, doesn't work for me in Linux.

[Andareed]

Any function in windows crt that starts with an underscore is non-standard (either altered or non-existant in ANSI C).