Ryan V Posted April 17, 2004 Share Posted April 17, 2004 Maybe you guys might be able to solve this math question thats stumped me :blush: [Was never good with Trig] 1. Ashkar needs to measure the distance across the lake shown below. He paces off 70m to a tree N near the North shore. He returns to A and paces off 80m to a tree S near the South shore. He then returns to A and using a surveyor?s transit measures the angle at A as 75 degrees. [see Attached Picture] a) What Law do you have to use b) What is distance NS to the nearest meter? Anyhelp with these questions would be Appreciate:):) . Link to comment Share on other sites More sharing options...
elliot Posted April 17, 2004 Share Posted April 17, 2004 NS= sqrt(na^2 + as^2 - 2*NA*AS*cosA) cosine rule 78m do i win a prize? Link to comment Share on other sites More sharing options...
vie7now Posted April 17, 2004 Share Posted April 17, 2004 NS^2 = (AN^2) + (AS^2) - (2xANxAS) x COS 75 It's the cosine law. Damn you elliot. :pinch: :D -0 Link to comment Share on other sites More sharing options...
Ryan V Posted April 17, 2004 Author Share Posted April 17, 2004 ummm...the great satifaction that you help a fellow member lolz and cash reward coming soon :whistle: Link to comment Share on other sites More sharing options...
Recommended Posts