[PHP] Error in Image Last Viewed Script

[TimRogers]

<?php
header("Content-type: image/png");
$datafile = "last-seen.dat";
$loadfile = fopen($datafile, 'r');
$data = fread($loadfile, filesize($datafile));
fclose($loadfile);

$im = imagecreatefrompng("template.png");
$textcolour = imagecolorallocate($im, 0, 0, 0);
imagestring($im, 1, 140, 7, $data, $textcolour);

$writing = fopen($datafile, 'w');
$towrite .= date('d');
$towrite .= " ";
$towrite .= date('F');
$towrite .= " ";
$towrite .= date('Y');
$towrite .= " at ";
$towrite .= date('H');
$towrite .= ":";
$towrite .= date('i');
$towrite .= ":";
$towrite .= date('s');

fwrite($writing, $towrite);
fclose($writing);
?>

In Firefox if you visit it you get the URL of the page printed out, and for some reason it's not highlightable, and in IE you just get an image error box. Why?

http://www.tim-rogers.co.uk/lastseen/bar.php

[jtchange]

i think you need to use the imagepng() function to output the image...you have the image created, but you aren't outputting it.

imagepng($im);

more info: http://us3.php.net/imagepng

[TimRogers]

Thank you :) That did it!